Objective – To investigate the relationship between the
molality and the boiling point of a solution.
Hypothesis:
When more solute (benozoic acid) we add to the
acetone, the vapor pressure of the solvent is less than the vapor pressure of
the pure solvent. The boiling point of a solution will be higher than the
boiling point of the pure solvent because the solution (which has a lower vapor
pressure) will need to be heated to a higher temperature in order for the vapor
pressure to become equal to the external pressure. In this case, when more
benzoic acid we have in the solution, more it will take to boil.
Table:
Mass
of benzoic acid in solution (g)
|
Molality
(mol/kg)
|
First
run - Boiling point (oC)
|
Second
run - Boiling point (oC)
|
Average
boiling point
(oC)
|
Change
in boiling point compared to pure acetone (oC)
|
0
|
0
|
56.0
|
56.4
|
56.2
|
0.2
|
0.5
|
0.82
|
58.8
|
58.0
|
58.4
|
2.4
|
1.0
|
1.64
|
60.7
|
60.5
|
60.6
|
4.6
|
1.5
|
2.46
|
51.5
|
51.3
|
51.4
|
5.4
|
2.0
|
3.28
|
65.3
|
64.7
|
65.0
|
9
|
2.5
|
4.0
|
67.1
|
67.1
|
67.1
|
11.1
|
Evaluation:
We think it was a complex experiment because we
confused many times with the tested and this makes that we couldn´t finished
correctly the experiment.
The first problem was to calculate the measurement
because we calculated using the eye line and this is not very accurate. A good
solution is to change the mL into grams so we can calculate it in the balance
and we have the exact measure, but this will takes us lot of time and it would
slow down our experiment and we don´t have so much time.
When we were going to make the graph using the table,
we saw that there were two wrong results in the table, the one using 1.5 mass of benzoic acid in solution. To don´t
put this mistake in the graph we remove it and we don´t use it in the graph.
Other big problem was when the liquid evaporate we
lose solution and this affect directly to the project and when the acetone
boils, and starts to grow bubbles, we also lose liquid and the concentration.
We have to take care and being precise when we calculate the temperature
because it could react and we can lose liquid because of the bubbles or if it
boils, the acetone will evaporate and we also lose liquid, we will have other
results.
Also a problem was when we poured acetone in the bunk
and this affected in the temperature so we could have different results. To
solve this problem, we have to be precise with the temperature because we know
that the bunk is not going to be at the temperature we have, so a good idea
would be, turn to the higher temperature and pay attention to the thermometer
and the temperature it marks when it reacts. Finally we have to be precise with
the temperature because when we get the test tube outside from the bunk the
temperature will cool down, so we have to see when it reacts and see the
correct temperature when the test tube is in the bunk.
Conclusion:
We said in the hypothesis that the more solute (benozoic
acid) we add to the acetone, the vapor pressure of the solvent is less than the
vapor pressure of the pure solvent, so the boiling point of a solution will be
higher than the boiling point of the pure solvent.
In the graph we can see that with more concentration,
the boiling point will increase, the line grows up. The function is directly
proportional because when x grows also y grows.
When we finished the experiment and we get all the
data we could prove that the hypothesis was correct because the boiling point
of a solution will be higher than the boiling point of the pure solvent.
References:
Chemspider.com, (2015). Benzoic acid | C7H6O2 | ChemSpider. [online] Available at:
http://www.chemspider.com/Chemical-Structure.238.html [Accessed 21 Feb. 2015].
Webbook.nist.gov, (2015). Acetone. [online] Available at:
http://webbook.nist.gov/cgi/cbook.cgi?ID=67-64-1&Type=IR-SPEC&Index=QUANT-IR,0
[Accessed 21 Feb. 2015].


I would like to have seen you use the BP elevation equation to support your hypothesis.
ResponderEliminarTables should have a title.
The conclusion ould be improved by comparing your results with the theoretical results (using the equation).
The evaluation contains some good points but is a little unclear in its explanation.
THERE IS NO GRAPH!!!
The graphs are ok but missing titles and a line of best fit.
ResponderEliminar4/8 --> 5